# Line slope calculator 4x-y=19

**Straight line given by points A[5; 1] and B[6; 5]**

## Calculation:

**Slope-intercept form of line:**y = 4x-19

**Canonical form of the line equation:**4x-y-19 = 0

**Parametric form of the line equation:**

x = t+5

y = 4t+1 ; t ∈ R

**Slope:**m = 4

**Slope angle of line: φ =**75°57'50″ = 1.3258 rad

**X intercept:**x

_{0}= 4.75

**Y intercept:**y

_{0}= q = -19

**Distance line from the origin:**d

_{0}= 4.6082

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(1; 4)

**Normal vector: n =**(4; -1)

**Midpoint of the segment AB: M =**[5.5; 3]

**Perpendicular Bisector equation:**x+4y-17.5 = 0

**Vector OA = (5; 1) ; |OA| = 5.099**

**Vector OB = (6; 5) ; |OB| = 7.8102**

**Scalar product OA .OB = 35**

**Angle ∠ AOB = 28°29'44″ = 0.4973 rad**